Question

If a train is travelling at 10m/s starts to accelerate at 1m/s (square) for 15s on a straight track, it’s final velocity and in m/s is??

Please someone help me out, please it’s urgent

Answer 1

Explanation:

Data: Vi= 10m/s; a=1m/s^2; delta T =20 s → find displacement during the time interval of 20s

(1) Equation for constant acceleration: Vf= Vi + a*deltaT= 10m/s +(1m/s^2)*(20s) = 30 m/s

(2) Equation for constant acceleration: d = (Vf)^2 - (Vi)^2/ 2*a = (30)^2 - (10)^2/2= (900 - 100)/2 = 800/2 = 400 m= displacement during 20s with constant acceleration

Answer 2

Answer:

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Explanation:

v= u + at

=> v= 10 + 1× 15

=> v= 25 m/ sec