If a train runs at 40 km/hr, it reaches its destination late by 11 minutes, but if it runs at 50 km/hr, it is late by 5 minutes only. find the correct time for the train to complete its journey.
Answers
Answered by
6
Hi Jayakumar,
Let d be the distance
let t be the time taken (without being late) = correct time = t
the hint here is that the distance remains same in both cases
so the distances in given two cases can be equated to each other
speed = distance / time
distance = speed * time
note: 11 minutes = 11/60 hrs
Equating as distance are same
40*(t+11/60) = 50*(t+5/60)
=> 40t + 440/60 = 50t - 250/60
=> 10t = 440/60 + 250/60
=> 10t = 690/60
=> t = 69/6 = 11.5 hrs = 11h 30minutes
so the correct time taken for journey will be = 11hrs 30minutes
Hope it helped.
Let me know if any doubts.
Cheers !!!
Let d be the distance
let t be the time taken (without being late) = correct time = t
the hint here is that the distance remains same in both cases
so the distances in given two cases can be equated to each other
speed = distance / time
distance = speed * time
note: 11 minutes = 11/60 hrs
Equating as distance are same
40*(t+11/60) = 50*(t+5/60)
=> 40t + 440/60 = 50t - 250/60
=> 10t = 440/60 + 250/60
=> 10t = 690/60
=> t = 69/6 = 11.5 hrs = 11h 30minutes
so the correct time taken for journey will be = 11hrs 30minutes
Hope it helped.
Let me know if any doubts.
Cheers !!!
Answered by
0
so the answer is 19 min
Step-by-step explanation:
let the normal speed be s km/h and normal time be t hours
d =. st
according to question distance is same ..1
now , train 1 - 40(t+11/60)
train 2 - 50(t+5/60)
from equation 1 we can say that
4t + 44/60= 5t +25/60
t =19/60hrs
= 19 min
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