Question

If a train runs at 40 kmph it reaches its destination late by 11 minutes. But if it runs at
so kmph it is late by 5 minutes only. Find the distance to be uwezed by the trainu​

Answer 1

Given :

Speed of train is 40 km/hr and its late by 11 min or 11/60 hr.  

In other case it's also given speed of train is 50 km/hr and late by 5 min

or 5/60 hr.

Let the train covered 'd' km distance.

The journey let it took 't' hr time.

                                                             

We have difference in late of time i.e.

11/60 - 5/60 = 1/10

We know,

Time = Distance/Speed

A.T.Q. (Answer The Question)

d/40 - d/50 = 1/10

d/10 (1/4 - 1/5) = 1/10

d(1/20) = 1

d = 20 km

Hence , the distance to be covered by the train is 20 km .

OR

Let us consider the time of journey be T hrs

then,as distance is same, then

A/Q,

⇒40( T +11/60) =50 (T- 5/60)

⇒T= 23/30 hr

distance= speed ×time

             = 40×23/30

             =92/3 km

             =30.66 km