Question

if a train runs at 40km/ph it reaches destination late by 11minutes but it runs 50 km/pH it is late by 5 minutes only .find the distance to be covered by train

Answer 1

Okay so,

Let the actual time taken be x
And the distance be y

Therefore when the speed of the train is 40km/h the time taken will be : x +11


Therefore when the speed of the train is 50km/h the time taken will be : x +5

Then as we know - Speed * time = distance

We can now make two equations

1) 40 * (x+11) = y

2) 50 * (x+5) = y

Then we solve the simultaneous equations

Opening the brackets

40x + 440 = y

50x + 250 = y
————————————————

y - 40x = 440

y - 50x = 250

We subtract both the equations

————————————————-

y - 40x = 440

(-)y (+)50x = (-)250

Therefore,

10x = 190

x = 19.

This the time taken. Now we just substitute the valie into one of the equations.

40 * (x+11) = y

40 * (19+11) = y

40 * 30 = y

y = 1200. This the distance to be cover.