Question

If a train travelling at 72 kmph is to be brought to rest in a distance of 200 meters then it's retardation should b

Answer 1

v sq.-u sq. = 2as
0-72sq. = 2 × a × 0.2
0-5184= 4/10 × a
-5184×10/4 =a
-12960=a
retardtn =12960 m/s sq.