If a trainagle abc is right angled at c then the value of cos(a+b)
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in any triangle : A + B + C = 180°
so, here,
C = 90°
therefore :
A + B = 90°
and we have :
cos(A + B) = cos90° = 0
so, here,
C = 90°
therefore :
A + B = 90°
and we have :
cos(A + B) = cos90° = 0
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