If a truck starts from rest and it has acceleration of 4 m/s2 for 5 seconds, calculate its final velocity. What will be the distance travelled by the truck during the time interval?
That is 4 metre per second square...please solve it.
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Final velocity of truck is 20 m/s and distance travelled by truck is 50 m.
Solution
As the truck starts from rest, so initial speed i.e. u = 0 m/s
Acceleration (a) = 4 m/s²
Time (t) = 5 seconds.
We will use 1st equation of motion to find final velocity of truck :
* 1st equation → v = u + at
⇒ v = 0 + 4 × 5
⇒ v = 0 + 20
⇒ v = 20 m/s
∴ Final velocity of truck = 20 m/s
Now we will use 3rd equation of motion to find distance travelled by truck :
* 3rd equation → v² - u² = 2as
⇒ 20² - 0² = 2 × 4 × s
⇒ 400 - 0 = 8s
⇒ 8s = 400
⇒ s = 400/8
⇒ s = 50 m
∴ Distance travelled by truck during time interval = 50 m
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