If a vehicle is accelerated to 5 ms⁻², how much time does it take to attain a velocity of 27 ms⁻¹ which initially starts With 2 ms⁻¹
Answers
Answered by
2
a=5 m/s
t=?
V=27 m/s
u=2 m/s
a=v-u/t
t=v-u/a
t=27-2/5
t=25÷5
t=5 seconds
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t=?
V=27 m/s
u=2 m/s
a=v-u/t
t=v-u/a
t=27-2/5
t=25÷5
t=5 seconds
hope it helps u..
Plz Mark me as a brainlist......
Answered by
3
As per the question,
Acceleration, a = 5 m/s^2
Final Velocity, v = 27 m/s
Initial Velocity, u = 2 m/s
Time take = ?
The first equation of motion,
v = u + at
27 = 2 + 5 * t
27 – 2 = 5 * t
25 = 5 * t
25/5 = t
t = 5 sec
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