If a vehicle is running with a velocity of 72 km / hr. What should be the retardation of the vehicle to stop it 20 m ahead?
Answers
Answered by
12
Answer:
-10 ms^2
Explanation:
as stopping distance=u^2/2a
u=72km/hr.=20m/s
20×20/2a=20m(given)
on solving we get
a=10ms^2
Answered by
14
v=0. u=72*5/18=20
s=20m
from third equation of motion we have
v²=u²+2as
0=20²+2*a*20
0=400+40a
-4000=40a
a=-400/40
a=-10m/s²
s=20m
from third equation of motion we have
v²=u²+2as
0=20²+2*a*20
0=400+40a
-4000=40a
a=-400/40
a=-10m/s²
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