If a vehicle starts from rest and moves with a uniform acceleration of 10meters per seconds square for 10 seconds, determine the distance covered in the last second of the motion
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Given that,
Acceleration (a) = 10m/s²
Time (t) = 10 sec.
Initial velocity (u) = 0m/s²
(as the vehicle is starting from rest.)
To find,
The distance travelled in the last seconds = ?
From the second equation of motion,
s = ut + 1/2 at²
s = 0 * 10 + 1/2 * 10 * 10 * 10
s = 0 + 1/2 * 1000 s = 1/2 + 1000
s = 500m
Therefore, the distance travelled in the last seconds is 500m.
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