Question

If a velocity of a particle is given by V= 10 + 2t^2 m/s . The average acceleration between 2 and 5 second is

Answer 1

Answer:

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Explanation:

Given ----->

velocity of particle ( v ) = 10 + 2t^2 m/s

To find average acceleration,

Average acceleration =

change in velocity / change in time =

V5 - V2 / 5-2

= V5 - V2 / 3 .............(1)

Now, Putting value of t = 5s.

V5 = 10 + 2 (5 ) ^2 m/s

V5 = 10 + 50 m/s = 60 m/s.

Now, Putting value of t = 2s.

V2 = 10 + 2(2)^2 m/s

V2 = 10 + 8 m/s = 18 m/s.

Putting values of V2 and V5 in eq. ( 1)

=

Average acceleration = ( 60 - 18 / 3 ) m/s

= 42 / 3 m/ s

= 14 m/s.

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