Question

If a vertex of a triangle be (1, 1) and the middle points of the sides through it be (-2, 3) and (5, 2), find the other vertices.

Answer 1

Step-by-step explanation:

Vertex of triangle is (1,1) and midpoint of sides through this vertex is (−1,2) and (3,2)

Co-ordinate of B is (x,y)

co-ordinates of B is(

2

1+x

=−1,

2

1+y

=1)::((x,y):(−3,3))

Similarly, co-ordinate of C comes out to be (5,3)

Thus centroid is,

3

1−3+5

,

3

1+3+3

⇒(1,

3

7

) ...(hint: using formula of centroid)

Answer 2

$\huge{SOLUTION!!...}$

1+x/2,1+y/2=-2,3

1+x/2=-2. y+1=6

X+1=-4. y=5

X=-3

One vertices is (-3,5)

1+x/2,1+y/2=5,2

1+x=10. 1+y=4

X=9. y=3

Another vertices is (9,3)

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