Prove that the points (4, 5), (7, 6), (6, 3), (3, 2) are the vertices of a parallelogram. Is it a rectangle.
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Let A(4, 5), B(7, 6), C(6, 3), and D(3, 2) be the given points. And, P the points of intersection of AC and BD. Coordinates of the mid-point of AC are Coordinates of the mid-point of BD are Thus, AC and BD have the same mid-point. Hence, ABCD is a parallelogram Now, we shall see whether ABCD is a rectangle. We have, So, ABCD is not a rectangle
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