Question

If a virtual image is formed along the principal axis 10.0 cm from a concave mirror with the focal length 15.0 cm, what is the object distance from the mirror? a. 30.0 cm b. 10.0 cm c. 12.4 cm d. 6.0 cm​

Answer 1

Answer:

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Answer 2

Let d be the distance from the object to the mirror, f be the distance from image to the mirror and F be the focal length. The relation between these parameters is (for the virtual image)

$\frac{1}{d} - \frac{1}{f} = \frac{1}{F}$

$\frac{1}{d} = \frac{1}{f} + \frac{1}{F}$

$\frac{1}{10} + \frac{1}{15} = \frac{1}{6} cm$

d=6.0cm