Question

If a wheel of diameter 2 m makes 60
revolutions/second, then the linear speed of a point on
its circumference will be
60 pie m/s
90 pie m/s
120 pie m/s
150 pie m/s​

Answer 1

Answer:

The Answer is ofcourse 60 πm/s

Explanation:

I gave the paper of AIATS, in which this question came and I got full in Physics section.

Answer 2

Answer:

The linear speed of a point on the circumference of the wheel is equal to 120π m/s.

Therefore, the option (c) is correct.

Explanation:

Given, the diameter of the wheel, $d=2m$

∴ The radius of the wheel, $r=1m$

The frequency of the wheel, f = 60 revolutions/sec

We know that the angular velocity (ω) is given by:

$\omega =2\pi f$                                                                        ..............(1)

Put the value of f in eq.(1);

$\omega=2\pi *(60)$

$\omega= 120\pi\; rad/sec$

Now, the relation between the angular velocity (ω) and linear velocity (v) is:

$v=r\omega$              

Put the value in 'r' and ω in above equation:

$v=(1)(120\pi )$

$v=120\pi \;ms^{-1}$

Therefore, the linear speed of the wheel is equal to 120π m/s.