if a wheel starts from rest and attains an angular velocity of 300rev/sec in 1 min find it's angular acceleration
Answers
Answered by
1
Answer:
From kinematics laws for rotational motion:
ω=ω
0
+αt ..(1)
θ=θ
0
+ω
0
t+
2
1
αt
2
....(2)
ω
2
−ω
0
2
=2αθ.....(3) where,
ω is final angular velocity
ω
0
is initial angular velocity
θ is angular displacement
α is angular acceleration and t is time
From(1) , 20=0+α×10
α=2rad/s
2
From(3) , (20)
2
−0
2
=2×2×θ
400=4θ
θ=100rad
Answered by
1
From kinematics laws for rotational motion:
ω=ω0+αt ..(1)
θ=θ0+ω0t+21αt2....(2)
ω2−ω02=2αθ.....(3) where,
ω is final angular velocity
ω0 is initial angular velocity
θ is angular displacement
α is angular acceleration and t is time
From(1) , 20=0+α×10
α=2rad/s2
From(3) , (20)2−02=2×2×θ
400=4θ
θ=100rad
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