If a wire is stretched to double its length with resistance 4 ohm .calulate the new resistance
Answers
Answered by
0
R=(p*l)/a
Now new resistance
R1=(p*2l)/a
=2(p*l)/a
=2R
R1=2*4
=8 ohm
Now new resistance
R1=(p*2l)/a
=2(p*l)/a
=2R
R1=2*4
=8 ohm
Similar questions