if a wire of resistance R is cut into n equal parts all parts are first connected in series and then in parallel calculate ratio of series and parallel combination of resistors.
Answers
Answered by
1
Answer:
As we know R∝l(length of wire)
and we are cutting the wire into n equal parts, so each new formed wire's resistor
⇒R
1
=R
2
=R
3
=R
4
=R
5
=...R
n
=
n
R
as the diagram shows, we are connecting them in parallel series then equivalent resistance of combination is given by R
eq
⇒
R
eq
1
=
R
1
1
+
R
2
1
+
R
3
1
+
R
4
1
+...+
R
n
1
⇒
R
eq
1
=
R
n
+
R
n
+
R
n
+...+
R
n
(n times)
⇒
R
eq
1
=(
R
n
)×n
⇒R
eq
=
n
2
R
correct option will be (D)
Explanation:
Answered by
2
Answer:
Explanation:
nR for series and
for parallel
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