if a work in 4 days and b can work in 6 days then in how many days both work
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Answer:
A can do a job in 4 days and B can do the same job in 6 days. If A’s efficiency increases to 4/3 times, then by how many times does B have to reduce his efficiency so that the work can be completed by both of them in two days?
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A can do a job in 4 days and B can do the same job in 6 days so the Total work is 24.
and efficiency of A is 24 work/4 days = 6 work/day
efficiency of B is 24 work/6 days = 4 work/day
when they work together ,
one day work of A and B is 6+4 = 10 work/day
they can finish 24 work in 2.4 days.
now as per the question efficiency of A is increased by 4/3 times
i.e.
6 * 4/3 = 8
so now A can do 8 work/day
to finish the 24 work in 2 days… they have to work with the efficiency of 12 work day.
A’s increased efficiency is 8 work /day. and B’s original efficiency is 4 work/day.
total work in day is 12 . so there is NO need to reduce the efficiency of B.