Question

if a worker is holding a box of mass 200 kg to a height of 2 m for 10 s, what is the work done by the worker?

Answer 1

Answer:

4,000 joules.

Explanation:

Question says that, A worker is holding a box of 200kg to a height of 2m for 10 seconds.

Find the work done by the worker.

Here,

The work done is a potential energy.

We know,

→ P.E.(potential energy) = mgh

Where,

• m is the mass of the object.
• g(acceleration due to gravity) = 9.8m/s
• h is the height.

Substituting the given values,

→ 200 × 2 × 10

→ 4000 joules.

∴ Work done my the worker is 4,000 joules.

__________________________

NOTE:

• Potential energy is a stored energy of a object due to its position.
• P.E. is calculated by the formula = mgh
• Where, m is mass, g is acceleration due to gravity, and h denotes the height.

UNITS:

• P.E. is measured by joules.
• m = kg.
• g = m/s
• h = metres.

Answer 2

Answer:

Given :-

• A worker is holding a box of mass 200 kg to a height of 2 m for 10 seconds.

To Find :-

• What is the work done by the worker.

Formula Used :-

$\clubsuit$ Work Done Formula :

$\bigstar \: \: \sf\boxed{\bold{Work\: Done =\: mgh}}\: \: \: \bigstar$

where,

• m = Mass (in kg)
• g = Acceleration due to gravity (in m/s²)
• h = Height (m or metres)

Solution :-

Given :

• Mass = 200 kg
• Height = 2 m
• Acceleration due to gravity = 10 m/s²

According to the question by using the formula we get,

$\implies \bf Work\: Done =\: mgh$

$\implies \sf Work\: Done =\: 200 \times 10 \times 2$

$\implies \sf Work\: Done =\: 2000 \times 2$

$\implies \sf Work\: Done =\: 4000$

$\implies \sf\bold{\underline{Work\: Done =\: 4000\: J}}$

$\therefore$ The work done by the worker is 4000 Joules .