If a=x-3y, b = 2x + 3y and c = -3x + 7, show that a + b + c = 7.
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3
Answer:
Given value of a = x - 3y
Given value of b = 2x + 3y
Given value of c = -3x + 7
Given equation = a + b + c
We can find the answer the equation by substituting the values of a, b and c with their respective constants.
a + b + c
⇒ x - 3y + 2x + 3y + (-3x + 7)
⇒ x - 3y + 2x + 3y - 3x + 7
Now, we have to group the like terms together and add or subtract them.
⇒ x + 2x - 3x - 3y + 3y + 7
⇒ 3x - 3x + 0 + 7
⇒ 0 + 0 + 7
⇒ 7
∴ Hence, the value of a + b + c is 7.
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Answered by
2
Answer:
a=x-3y
b=2x+3y
c=-3x+7
A/Q
a+b+c=(x-3y)+(2x+3y)+(-3x+7)
= x-3y+2x+3y-3x+7
=3x-3x-3y+3y+7
= 7(proved)
a+b+c=7
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