Question

If a^x = b, b^y = c, c^z = a, prove that xyz = 1.​

Answer 1

Given,

aˣ = b, b^{y} = c ,  c^{z} = a  

c^{z} = a, c is what it is  b^{y}  

so,  b^{yz} = a  

Now b is what is  a^{x}  

[a^{x}]^{yz} = a  

a^{xyz} = a  

a^{xyz} =  a^{1}  

Therefore,

xyz = 1

[Hence Proved]