Question

if a(x-y)+a^2=b(y-z)+b^2=c(z-x)+c^2, then show = a+b+c/ (1/a + 1/b + 1/c)

Answer 1

Answer:

Adding, subtracting, multiplying, and dividing. Both sides of an equation will stay equal if we add the same integer to both sides.

Step-by-step explanation:

What is an equation?

$\frac{x}{y+z} = a ; \frac{y}{x+z} = b\\\\\frac{z}{x+y} = c\\\\\frac{1}{1+a} + \frac{1}{1+b} + \frac{1}{1+c} =$

(a) 2 (b) 3 (c) 6 (d)

= $x +y+z$

An equation is a mathematical expression that includes the equals sign. Algebra is frequently used in equations. When you don't know the precise quantity in a computation, you utilise algebra. Identity equations and conditional equations are the two types of equations. An identity holds true for all possible values of the variables. A conditional equation is valid only for certain values of the variables. An equation is a collection of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division that are balanced by an equal sign. The left-hand side (LHS) is on the left side of the equation, while the right-hand side (RHS) is on the right side of the equation (RHS).

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