Question

if x+y=8 and xy=12 then find the value of x and y.​

Answer 1

${\huge{\boxed{\tt{\color{red}{Sølutiøn : -}}}}}$

Here, x + y = 18 and xy = 12

Then x = 18 - y

Substituting the value of x, we have

x (18 - y) = 12

$\longrightarrow$ 18x - xy = 12

$\longrightarrow$ 18x - 12 = 12

$\longrightarrow$ 18x = 12 + 12 = 24

$\large{\therefore{\boxed{x = \frac{24}{18}}}}$

$\large{\therefore {\boxed{x = \frac{4}{3}}}}$

And $\large{\therefore{\boxed{y = 12 × \frac{3}{4} = 9}}}$

$\pink{Hope \: it \: helps}$

Answer 2

Answer:

x+y=8

x=8-y

xy=12

(8-y)y=12

8y-y²=12

y²-8y-12=0

y²-6y-2y-12=0

y(y-6)-2(y-6)=0

(y-6)(y-2)=0

y-6=0

y=6

y-2=0

y=2

taking y=2

x=8-2=6

taking y=6

x=8-6=2