Question

If a, ß, y are the angles of a triangle ABC, show that
Q
cot alpha/2
+ cot beta/2
+ cot gema/2
= cot alpha/2 x cot beta/2 x cot gema/2

Answer 1

Answer:

α,β,γ are in A.P.

α+γ=2β

β=  

2

α+γ

​  

 

cotβ=cot  

2

α+γ

​  

 

=  

sin  

2

α+γ

​  

 

cos  

2

α+γ

​  

 

​  

 

=  

2sin  

2

α−γ

​  

sin  

2

α+γ

​  

 

2sin  

2

α−γ

​  

cos  

2

α+γ

​  

 

​  

 

=  

cosγ−cosα

sinα−sinγ

​  

 

cotβ=  

cosγ−cosα

sinα−sinγ

​

Step-by-step explanation: