If a, ß, y are the angles of a triangle ABC, show that
Q
cot alpha/2
+ cot beta/2
+ cot gema/2
= cot alpha/2 x cot beta/2 x cot gema/2
Answers
Answered by
1
Answer:
α,β,γ are in A.P.
α+γ=2β
β=
2
α+γ
cotβ=cot
2
α+γ
=
sin
2
α+γ
cos
2
α+γ
=
2sin
2
α−γ
sin
2
α+γ
2sin
2
α−γ
cos
2
α+γ
=
cosγ−cosα
sinα−sinγ
cotβ=
cosγ−cosα
sinα−sinγ
Step-by-step explanation:
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