If a1, a2, a3,...... are in AP then ap, aq, ar, are in AP if p, q, r are in
(a) AP
(b) GP
(c) HP
(d) none of these
Answers
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p, q, r are in AP if a₁ , a₂ , a₃ ...................... are in AP and ap, aq, ar, are in AP
Step-by-step explanation:
a₁ , a₂ , a₃ ...................... are in AP
d is common difference
=> a₂ = a₁ + d
aₙ = a₁ + (n - 1)d
d is common difference
ap = a₁ + (p - 1)d
aq = a₁ + (q - 1)d
ar = a₁ + (r - 1)d
ap, aq, ar, are in AP
=> ap + ar = 2 aq
=> a₁ + (p - 1)d + a₁ + (r - 1)d = 2 ( a₁ + (q - 1)d)
=> pd + rd = 2qd
Dividing by d from both sides
=> p + r = 2q
=> p , q & r are in AP
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