Question

pls integrate sin2x.cos3x

Answer 1

Hey Mate!!!

Sin ( 2x ) Cos ( 3x ) = 1 / 2 { Sin ( 6x ) + Sin ( -x )


So, integration of Sin ( 2x ) Cos ( 3x )


is equal to 1 / 2 { (- Cos ( 6x ) / 6 ) + Cos ( x ) }