If A1,A2,A3,...... is an Arithmetic progression with common difference 1 and A1+A2+A3+A4+.......+A98=137 then A2+A4+A6+.....+A98=
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Answer:
A2+A4+A6+.....+A98=184
Step-by-step explanation:
by formula sn=n/2(2a+(n-1)d)
we will get a=-47
and s98 as 184
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