Math, asked by surenderkaran5726, 2 months ago

If A1,A2,A3,...... is an Arithmetic progression with common difference 1 and A1+A2+A3+A4+.......+A98=137 then A2+A4+A6+.....+A98=

Answers

Answered by 9129810497adi

0

Answer:

A2+A4+A6+.....+A98=184

Step-by-step explanation:

by formula sn=n/2(2a+(n-1)d)

we will get a=-47

and s98 as 184

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