if a1/a2=b1/b2 but a1/a2#c1/c2 or b1/b2 #c1/c2 then how many solution the equation has?
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Explanation :a1x + b1y + c1 = 0a2x + b2y + c2 = 0then a1/a2 = b1/b2 ≠ c1/c2 shows equation has no solution.
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