if a² + 1/a² = 18 find rhe value of a + 1/a and a -. 1/a
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EXPLANATION.
⇒ (a² + 1/a²) = 18.
As we know that,
Formula of :
⇒ (x + y)² = x² + y² + 2xy.
We can write equation as,
⇒ (a + 1/a)² = a² + 1/a² + 2(a)(1/a).
⇒ (a + 1/a)² = a² + 1/a² + 2.
Put the values of (a² + 1/a²) = 18 in equation, we get.
⇒ (a + 1/a)² = 18 + 2.
⇒ (a + 1/a)² = 20.
⇒ (a + 1/a) = √20.
⇒ (a + 1/a) = 2√5.
As we know that,
Formula of :
⇒ (x - y)² = x² + y² - 2xy.
Using this formula in the equation, we get.
⇒ (a - 1/a)² = a² + 1/a² - 2(a)(1/a).
⇒ (a - 1/a)² = a² + 1/a² - 2.
Put the values of (a² + 1/a²) = 18 in equation, we get.
⇒ (a - 1/a)² = 18 - 2.
⇒ (a - 1/a)² = 16.
⇒ (a - 1/a) = √16.
⇒ (a - 1/a) = 4.
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