Question

If a²–3a+1 = 0, a is not equal to 0, then find a+1/a.​ No spamming please.

Answer 1

Step-by-step explanation:

Given,

${a}^{2} - 3a + 1 = 0$

$= > {a}^{2} + 1 = 3a \: \: .....(i)$

Now,

$a + \frac{1}{a} = \frac{ {a}^{2} + 1}{a}$

$= \frac{3a}{a} \: \: \: \: \: \: \: \: \: (from \: \: (i))$

$= 3$

Answer 2

Answer:

Answer:

$(a + \frac{1}{a} )= 3$

Step-by-step explanation:

Given that :-

a² - 3a + 1 = 0

⇒ a² - 3a = - 1 -------------------- (transporting 1 to RHS)

⇒ a(a - 3) = - 1 -----------------(TAKING 'a' COMMON )

⇒ a - 3 =  $\frac{-1}{a}$           ---------- ( TRANSPORTING 'a' on other side )

⇒ a - 3 +$\frac{1}{a}$  = 0

⇒ a +  $\frac{1}{a}$ = 3

Hence, the answer is 3.

_______________________