If (a2 - 4) x + (a + 2) x + a2 - a - 6 = 0 is an identity in x, then the value of a is
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The correct answer to this question is:
the values of a are 3 and -2
Step-by-step explanation:
Given,
(a² - 4) * x - (a + 2) * x + a² - a - 6 = 0
taking x as common
x * (a² - 4 - (a + 2)) + a² - a - 6 = 0
x * (a² - 4 - a - 2) + a² - a - 6 = 0
x * (a² - a - 6) + a² - a - 6 = 0
taking (a² - a - 6) as common
(a² - a - 6) * (x+1) = 0
x + 1 = 0 or (a² - a - 6) = 0
x + 1 = 0
x = -1
(a² - a - 6) = 0
a² - 3a + 2a - 6 = 0
a*(a - 3) + 2*(a-3) = 0
(a - 3) * (a + 2) = 0
a = 3 and a = -2
Hence, the values of a are 3 and -2
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