If a2 +62 = c2 , then log, (c - b) +log, (c + b) =
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Answered by
22
Answer:
Given a2 + b2 = c2
Now 1logc+a(b) + 1logc-a(b)
= logb(c+a) + logb(c-a)
= logb(c2-a2)
= 2logb(b) = 2
Answered by
0
Answer:
Explanation:
Given a2 + b2 = c2
Now 1logc+a(b) + 1logc−a(b)
= logb(c+a) + logb(c−a)
= logb(c2−a2)
= 2logb(b) = 2
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