if a2= b+c, b2= c+a, c2= a+b, then find the value of 1/1+a+1/1+b+1/1+c
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Answered by
32
1/1+a+1/1+b+1/1+c
=a/a+a²+b/b+b²+c/c+c²
=a/a+b+c + b/a+b+c + c/a+b+c
=a+b+c/a+b+c
=1
value is 1
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=a/a+a²+b/b+b²+c/c+c²
=a/a+b+c + b/a+b+c + c/a+b+c
=a+b+c/a+b+c
=1
value is 1
plzzz mark as brainliest...
Answered by
33
Thus, The value of is
Step-by-step explanation:
Given;
, , then
∴
Plug , and value in above equation;
∴ The value of is
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