Question

if a2+b2 =0 prove that a=0 and b=0

Answer 1

Step-by-step explanation:

a²+b²=0

=>a² = -b²

so, a=0,b=0

Answer 2

Step-by-step explanation:

In the question,

We have been provided that,

$a^{2}+b^{2}=0$

Now we have known that from the identity of the square of the terms that,

$\\(a+b)^{2}=a^{2}+b^{2}+2ab$

Now,

On putting the values in the above equation we get,

$\\(a+b)^{2}=0+2ab$

Now,

We know that the square of a term is always positive so for the sum of the squares to be = 0.

So, the only possible values of a and b are 0 and 0 only.

Hence, Proved.