If a²+b²=25 and ab=12 find a+b and a-b
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(a+b)^2 = a^2 +b^2 +2ab
a+b = √25+24
a+b = √49
a+b = 7
(a-b)^2 = a^2 +b^2 - 2ab
a-b = √25 - 24
a-b = √1
a-b = +1 or -1
Answered by
1
Answer:
Given : a²+b²=25 and ab=12
To find : a+b and a-b
Solution : we know that
(a+b)²= a²+b²+2ab
=> (a+b)² = 25+24 = 49 .............(from given )
=> a+b=√(49) = 7
(a-b)²=a²+b²-2ab
=>(a-b)²=25-24=1 .................... (from given)
=>a-b= √1 = 1
so a+b= 7 and a-b= 1
hope so it helps you dear
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