If (a² + b²)³ = (a³ + b³)² and ab not equals to 0 then the numerical value of a/b+b/a =?
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Answered by
21
Answer:
(a
2
+b
2
)
3
=(a
3
+b
3
)
2
∵(a
2
+b
2
)
3
=a
6
+b
6
+3a
2
b
2
(a
2
+b
2
)
∵(a
3
+b
3
)
2
=a
6
+b
6
+2a
3
b
3
⇒a
6
+b
6
+3a
2
b
2
(a
2
+b
2
)=a
6
+b
6
+2a
3
b
3
⇒a
2
+b
2
=
3
2
ab
So (
b
a
+
a
b
)
6
=(
ab
a
2
+b
2
)
6
=(
ab
3
2
ab
)
6
⇒(
3
2
)
6
=
729
64
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