if a2+b2=40and ab=12. then find a+b and a-b
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we know that
(a+b)²=a²+b²+2ab
=40+2*12
=40+24
=64
(a+b)=√64=±8
(a-b)²=a²+b²-2ab
=40-2*12
=40-24
=16
(a-b)=√16=±4
a+b=8
a-b=4
=====
2a=12
a=6
b=2
(a+b)²=a²+b²+2ab
=40+2*12
=40+24
=64
(a+b)=√64=±8
(a-b)²=a²+b²-2ab
=40-2*12
=40-24
=16
(a-b)=√16=±4
a+b=8
a-b=4
=====
2a=12
a=6
b=2
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