if a² + b² = 47,a - b = 3 ,find the value of ab.
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Step-by-step explanation:
Solution
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Using the identity is (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
It is given that a
2
+b
2
+c
2
=50 and ab+bc+ca=47, therefore,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
=a
2
+b
2
+c
2
+2(ab+bc+ca)
=50+(2×47)
=50+94=144
⇒(a+b+c)
2
=144
⇒a+b+c=−
144
,
144
⇒a+b+c=−12,12
Hence, the value of (a+b+c) is −12 or 12.
Answered by
0
Answer:
Using the identity is (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
It is given that a
2
+b
2
+c
2
=50 and ab+bc+ca=47, therefore,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
=a
2
+b
2
+c
2
+2(ab+bc+ca)
=50+(2×47)
=50+94=144
⇒(a+b+c)
2
=144
⇒a+b+c=−
144
,
144
⇒a+b+c=−12,12
Hence, the value of (a+b+c) is −12 or 12.
Step-by-step explanation:
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