if a2+b2=60 and ab=2 find the value of a+b
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Answered by
6
a^2 + b^2 = 60
Add 2ab on both side,
a^2 + b^2 + 2ab = 60 + 2ab
( a + b)^2 = 60 + 2(2)
a + b = √64
a + b= 8
Add 2ab on both side,
a^2 + b^2 + 2ab = 60 + 2ab
( a + b)^2 = 60 + 2(2)
a + b = √64
a + b= 8
Answered by
6
Hey
Here is your answer,
Given that,
a^2 + b^2 = 60
ab = 2
By using the identity ( a+b )^2 = a^2 + b^2 + 2ab
( a+b )^2 = 60 + 2 x 2
( a+b )^2 = 60 + 4
( a+b )^2 = 64
a+b = √64
a+b = 8
Hope it helps you!
Here is your answer,
Given that,
a^2 + b^2 = 60
ab = 2
By using the identity ( a+b )^2 = a^2 + b^2 + 2ab
( a+b )^2 = 60 + 2 x 2
( a+b )^2 = 60 + 4
( a+b )^2 = 64
a+b = √64
a+b = 8
Hope it helps you!
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