If a²+b² =9 ab=4. Find the value of 3(a+b)²(a-b)²
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HEYA !
Given that,
a² + b² = 9 and ab = 4
Now,
3 (a + b)² (a - b)²
= 3 (a² + b² + 2ab) (a² + b² - 2ab)
= 3 [ 9 + 2(4) ] [ 9 - 2(4) ]
= 3 (9 + 8) (9 - 8)
= 3 × 17 × 1
= 51
__________________________
Identity Used :
→ (a + b)² = a² + b² + 2ab
→ (a - b)² = a² + b² - 2ab
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Given that,
a² + b² = 9 and ab = 4
Now,
3 (a + b)² (a - b)²
= 3 (a² + b² + 2ab) (a² + b² - 2ab)
= 3 [ 9 + 2(4) ] [ 9 - 2(4) ]
= 3 (9 + 8) (9 - 8)
= 3 × 17 × 1
= 51
__________________________
Identity Used :
→ (a + b)² = a² + b² + 2ab
→ (a - b)² = a² + b² - 2ab
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