if a2 - b2 = b2 - c2 =c2 - a2 then show that ab-c2 /a- b + bc - a2 / b- c + ca - b2 / c- a=0
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If a2+b2+c2−ab−bc−ca=0, prove that a=b=c. ... Since the sum of square is zero then each term should be zero
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Consider, a2 + b2 + c2 – ab – bc – ca = 0 Multiply both sides with 2 , we get 2( a2 + b2 + c2 – ab – bc – ca) = 0 2a2 + 2b2 + 2c2 – 2ab ...
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