Question

If a²+b²+c²=125 and ab +bc +ca =50 ,find a+b+c​

Answer 1

Answer:

15

Step-by-step explanation:

a²+b²+c²=125

=>(a+b+c)^2 -2(ab+bc+ca)=125

=>(a+b+c)^2 -2(50)=125

=>a+b+c=√225

=15

So, a+b+c=15

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Thanks

Answer 2

Answer:

the correct answer is 15

Step-by-step explanation:

${a}^{2} + {b}^{2} + {c }^{2} = 125$

$ab + bc + ca = 50$

find a + b + c = ?

squaring

( a+b+ c) ^2= a^2+ b^2+c^2+2ab+2bc+2ac

= a^2+b^2+c^2+2(ab+bc+ac)

= 125+2(50)

=225

= (a+b+c)^2=225

square root on both sides

=a + b + c = + or - ✓ 225

= + or - 15

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