Question

If a2
+ b2 + c2
= 220 and a b +b c + c a=4 then find the value of a + b + c.​

Answer 1

this is the answer of your question

Answer 2

Answer:

$\sqrt{228}\\ or 15.1$

Step-by-step explanation:

(a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca

(a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)

we know (a+b+c)^2= 220 and  (ab+bc+ca)=4

(a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)

(a+b+c)^2=220+ 2(4)

(a+b+c)^2 =228

(a+b+c)=$\sqrt{228}$

a+b+c= 15.1

hope it helps :))