if a2+b2+c2=25 and ab+bc+ca=3 find a+b+c
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given- a2+b2+c2 = 250
ab+bc+ca=3
using identity (a+b+c)^2=a2+b2+b2+2ab+2bc+2ca
(a+b+c)^2= 250+2(3)
= 256
a+b+c= √256
=+- 16
(mean 16 is in positive and negative)
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