If a²+b²+c²=29 and a+b+c=9; find ab+bc+ca
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Since (a+b+c)²=a²+b²+c²+2 (ab+bc+ca)
Therefore (9)²=29+2 (ab+bc+ca)
➡81-29=2(ab+bc+ca)
Therefore, ac+bc+ca=52/2= 26
Hope it helps you...
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Answer:
- a+b+c whole square = a^2+b^2+c^2+2(ab+bc+ca)
- 9 whole square =29+2×(ab+bc+ca)
- 81=29+2(ab+bc+ca)
- 81-29/2=(ab+bc+ca)
- 26=(ab+bc+ca)
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