Question

If a²+b²+c²+3=2(a-b+c),what is the value of a+b+c
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Answer 1

Answer:

Hey friend!

Step-by-step explanation:

a^2+b^2+c^2+3=2(a-b-c)

a^2–2a+1+b^2+2b+1+c^2+2c+1=0

(a-1)^2+(b+1)^2+(c+1)^2=0

Therefore

a=1,b=-1,c=-1

Putting values of a,b,c;

2+1–1=2

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