Question

if a2+b2+c2=69 and ab+bc+ca=50 find a+b+c​

Answer 1

Answer:

Explanation:

(a+b+c)2=a2+b2+c2+2(ab+bc+ca)

2(ab+bc+ca)=(a+b+c)2-(a2+b2+c2)=169-69=100=(ab+bc+ca)=50

Answer 2

Answer:

59.6

Step-by-step explanation:

a2+b2+c2=69 , ab+bc+ca=50

(a+b+c)²= a²+b²+c²+ 2(ab+bc+ca)

or,  (a+b+c)² = 69 + 2 × 50

or,  (a+b+c)² = 71 × 50

or,  (a+b+c)² = 3550

or,  (a+b+c) = $\sqrt{3550}$

or, (a+b+c)  = 59.589 = 59.59 = 59.6