If a2+b2+c2=83 and a+b+c=15 then the value of ab+bc+ca is
A) 69 B) 70 C) 71 D) 72
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Answer:
81
Step-by-step explanation:
a²+b²+c²=83,
a+b+c=15,
On squaring both sides, we get
a²+b²+c²+2(ab+bc+ca)=225
- 83+2(ab+bc+ca)=225
- 2(ab+bc+ca)=142
ab+bc+ca=71
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