if a3=8,a7=24, then a10=? a>-4
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Heya !!
a3 = 8
A + 2D = 8 ---------(1)
And,
A7 = 24
A + 6D = 24 -----------(2)
From equation (1) we get,
A + 2D = 8
A = ( 8 - 2D ) ----------(3)
Putting the value of A in equation (2)
A + 6D = 24
8 - 2D + 6D = 24
4D = 24 - 8
D = 16/4
D = 4
Putting the value of D in equation (3)
A = 8-2D = 8 - 2 × 4
A = 8-8 = 0
First term ( A ) = 0
And,
Common difference ( D ) = 4
10th term = A + 9D
=> 0 + 9 × 4
=> 36.
Hence,
10th term of the given AP will be equal to 36.
a3 = 8
A + 2D = 8 ---------(1)
And,
A7 = 24
A + 6D = 24 -----------(2)
From equation (1) we get,
A + 2D = 8
A = ( 8 - 2D ) ----------(3)
Putting the value of A in equation (2)
A + 6D = 24
8 - 2D + 6D = 24
4D = 24 - 8
D = 16/4
D = 4
Putting the value of D in equation (3)
A = 8-2D = 8 - 2 × 4
A = 8-8 = 0
First term ( A ) = 0
And,
Common difference ( D ) = 4
10th term = A + 9D
=> 0 + 9 × 4
=> 36.
Hence,
10th term of the given AP will be equal to 36.
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